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重启动计算后was无法正常启动

系统 win2003sp2 系统 was6.1中文版本
was 使用单节点应用环境 默认安装概要文件为appsrv01  如果通过控制台停止服务器,关闭计算机,下次重启后was能正常启动
如果没有通过was控制台停止was,直接关闭计算机后,下次重启后was无法正常启动。
错误日志:
[09-3-17 9:22:39:031 CST] 00000014 WindowsServic 3   readAndDisplayServiceLogFile(), caught InterruptedException
[09-3-17 9:22:39:062 CST] 0000000a AdminTool     A   ADMU7704E: 在尝试启动与服务器相关联的 Windows 服务时失败:server1;
在执行 WASService.exe 时可能发生了错误:Starting Service: ncyaoNode01
Timed out waiting for service to respond to command, after 60 seconds.Failed to start service, or timed out while waiting for start to complete. Check the logs for details.
************ Start Display Current Environment ************
Host Operating System is Windows Server 2003, version 5.2 build 3790 Service Pack 2
Java version = J2RE 1.5.0 IBM J9 2.3 Windows Server 2003 x86-32 j9vmwi3223-20060504 (JIT enabled)
J9VM - 20060501_06428_lHdSMR
JIT  - 20060428_1800_r8
GC   - 20060501_AA, Java Compiler = j9jit23, Java VM name = IBM J9 VM
was.install.root = C:WebSphereAppServer
user.install.root = C:WebSphereAppServerprofilesAppSrv01
Java Home = C:WebSphereAppServerjavajre
ws.ext.dirs = C:\WebSphere\AppServer\java\lib;C:\WebSphere\AppServer\classes;C:\WebSphere\AppServer\lib;C:\WebSphere\AppServer\installedChannels;C:\WebSphere\AppServer\lib\ext;C:\WebSphere\AppServer\web\help;C:\WebSphere\AppServer\deploytool\itp\plugins\com.ibm.etools.ejbdeploy\runtime
Classpath = C:WebSphereAppServerprofilesAppSrv01properties;C:WebSphereAppServerproperties;C:WebSphereAppServerlibstartup.jar;C:WebSphereAppServerlibbootstrap.jar;C:WebSphereAppServer/lib/j2ee.jar;C:WebSphereAppServer/lib/lmproxy.jar;C:WebSphereAppServer/lib/urlprotocols.jar;C:WebSphereAppServerjavalibtools.jar
Java Library path = C:WebSphereAppServerjavajrebin;.;C:WebSphereAppServerjavajrebin;C:WebSphereAppServerbin;C:WebSphereAppServerjavabin;C:WebSphereAppServerjavajrebin;d:oracleproduct10.2.0db_1bin;C:WINDOWSsystem32;C:WINDOWS;C:WINDOWSSystem32Wbem;C:Program FilesATI TechnologiesATI.ACECore-Static;C:Program FilesCommon FilesThunder NetworkKanKanCodecs;C:Program FilesStormIICodec;C:Program FilesStormII
Current trace specification = *=info:com.ibm.*=all
************* End Display Current Environment *************
[09-3-17 9:23:22:640 CST] 0000000a ManagerAdmin  I   TRAS0017I: 启动跟踪状态是 *=info:com.ibm.*=all。
[09-3-17 9:23:22:640 CST] 0000000a WsServerContr 1   Executing executeUtilityOnWindows with args: C:WebSphereAppServerprofilesAppSrv01config ncyaoNode01Cell ncyaoNode01 server1
[09-3-17 9:23:22:640 CST] 0000000a WsServerContr 1   Getting WindowsService obj with: server1 and C:WebSphereAppServerprofilesAppSrv01config ncyaoNode01Cell ncyaoNode01 server1
[09-3-17 9:23:22:656 CST] 0000000a WindowsServic >  getWindowsServiceNameForServer() Entry
[09-3-17 9:23:22:656 CST] 0000000a WindowsServic 1   In executeCommand, args are: C:WebSphereAppServerbinWASService.exe -getServiceName server1 -profilePath C:WebSphereAppServerprofilesAppSrv01
[09-3-17 9:23:22:656 CST] 0000000a WindowsServic 1   Runtime.exec() returned process [email=java.lang.ProcessImpl@607c607c]java.lang.ProcessImpl@607c607c[/email]
[09-3-17 9:23:22:656 CST] 0000000c WindowsServic 3   inputRec == IBMWAS61Service - ncyaoNode01
[09-3-17 9:23:22:656 CST] 0000000a WindowsServic 1   retCode from childProcess.waitFor() is 0
[09-3-17 9:23:22:656 CST] 0000000a WindowsServic 3   exitCode = 0
[09-3-17 9:23:23:656 CST] 0000000a WindowsServic 1   Trying to new up WindowsService using serverName=server1, winServiceName=ncyaoNode01
[09-3-17 9:23:23:656 CST] 0000000a WindowsServic >  getServiceLogName() Entry
[09-3-17 9:23:23:656 CST] 0000000a WindowsServic 1   In executeCommand, args are: C:WebSphereAppServerbinWASService.exe -getServiceLogName server1 -profilePath C:WebSphereAppServerprofilesAppSrv01
[09-3-17 9:23:23:656 CST] 0000000a WindowsServic 1   Runtime.exec() returned process [email=java.lang.ProcessImpl@13ee13ee]java.lang.ProcessImpl@13ee13ee[/email]
[09-3-17 9:23:23:656 CST] 0000000e WindowsServic 3   inputRec == C:WebSphereAppServerprofilesAppSrv01logsncyaoNode01 Service.log
[09-3-17 9:23:23:656 CST] 0000000a WindowsServic 1   retCode from childProcess.waitFor() is 0
[09-3-17 9:23:23:656 CST] 0000000a WindowsServic 3   exitCode = 0
[09-3-17 9:23:24:656 CST] 0000000a WindowsServic 1   In executeCommand, args are: C:WebSphereAppServerbinWASService.exe -status ncyaoNode01
[09-3-17 9:23:24:656 CST] 0000000a WindowsServic 1   Runtime.exec() returned process [email=java.lang.ProcessImpl@60b060b0]java.lang.ProcessImpl@60b060b0[/email]
[09-3-17 9:23:24:656 CST] 00000010 WindowsServic 3   inputRec == The service is stopped.
[09-3-17 9:23:24:656 CST] 0000000a WindowsServic 1   retCode from childProcess.waitFor() is 1
[09-3-17 9:23:24:656 CST] 0000000a WindowsServic 3   exitCode = 1
[09-3-17 9:23:24:656 CST] 0000000a WindowsServic 1   In executeCommand, args are: C:WebSphereAppServerbinWASService.exe -status ncyaoNode01
[09-3-17 9:23:24:656 CST] 0000000a WindowsServic 1   Runtime.exec() returned process [email=java.lang.ProcessImpl@7bb47bb4]java.lang.ProcessImpl@7bb47bb4[/email]
[09-3-17 9:23:24:671 CST] 00000012 WindowsServic 3   inputRec == The service is stopped.
[09-3-17 9:23:24:671 CST] 0000000a WindowsServic 1   retCode from childProcess.waitFor() is 1
[09-3-17 9:23:24:671 CST] 0000000a WindowsServic 3   exitCode = 1
[09-3-17 9:23:24:671 CST] 0000000a WsServerContr 1   Window service status (1=stopped, 2=started, 3=not-registred) is 1
[09-3-17 9:23:24:671 CST] 0000000a AdminTool     A   ADMU7701I: 由于 server1 注册成作为 Windows 服务运行,因此启动该服务器的请求将由启动关联的 Windows 服务完成。
[09-3-17 9:23:24:671 CST] 0000000a WindowsServic 3   arrayList = [C:WebSphereAppServerbinWASService.exe, -start, ncyaoNode01]
[09-3-17 9:23:24:671 CST] 0000000a WindowsServic 1   In executeCommand, args are: C:WebSphereAppServerbinWASService.exe -start ncyaoNode01
[09-3-17 9:23:24:671 CST] 0000000a WindowsServic 1   Runtime.exec() returned process [email=java.lang.ProcessImpl@27aa27aa]java.lang.ProcessImpl@27aa27aa[/email]
[09-3-17 9:23:24:671 CST] 00000014 WindowsServic 3   waitForFileExist(C:WebSphereAppServerprofilesAppSrv01logsncyaoNode01 Service.log)
[09-3-17 9:23:25:171 CST] 00000014 EncodingUtils >  getProperEncoding Entry
[09-3-17 9:23:25:171 CST] 00000014 EncodingUtils 3   System.getProperty("file.encoding") is: GB18030
[09-3-17 9:23:25:171 CST] 00000014 EncodingUtils >  isPlatformWindows() Entry
[09-3-17 9:23:25:171 CST] 00000014 WindowsServic 3   *** returned readerencoding = GB18030
[09-3-17 9:24:24:687 CST] 00000018 WindowsServic 3   inputRec == Timed out waiting for service to respond to command, after 60 seconds.
[09-3-17 9:24:24:687 CST] 00000017 WindowsServic 3   inputRec == Starting Service: ncyaoNode01
[09-3-17 9:24:24:687 CST] 00000018 WindowsServic 3   inputRec == Failed to start service, or timed out while waiting for start to complete. Check the logs for details.
[09-3-17 9:24:24:687 CST] 00000017 WindowsServic 3   inputRec ==
[09-3-17 9:24:24:687 CST] 0000000a WindowsServic 1   retCode from childProcess.waitFor() is -1
[09-3-17 9:24:24:687 CST] 0000000a WindowsServic 3   -- interrupt the thread that is collecting stdout
[09-3-17 9:24:25:687 CST] 0000000a WindowsServic 3   exitCode = -1
[09-3-17 9:24:25:687 CST] 00000014 WindowsServic 3   readAndDisplayServiceLogFile(), caught InterruptedException
[09-3-17 9:24:25:687 CST] 0000000a WindowsServic 3   Timed out waiting for service to respond to command, after 60 seconds.Failed to start service, or timed out while waiting for start to complete. Check the logs for details.
[09-3-17 9:24:25:687 CST] 0000000a AdminTool     A   ADMU7704E: 在尝试启动与服务器相关联的 Windows 服务时失败:server1;
在执行 WASService.exe 时可能发生了错误:Starting Service: ncyaoNode01
Timed out waiting for service to respond to command, after 60 seconds.Failed to start service, or timed out while waiting for start to complete. Check the logs for details.
参与20

19同行回答

satan0208satan0208运维工程师北京华胜天成科技股份有限公司
删除trace。log可以正常启动了!我的也有过这样的问题显示全部
删除trace。log可以正常启动了!我的也有过这样的问题收起
电影/电视 · 2012-05-04
浏览914
shermantianshermantian系统工程师北京蓝海讯通科技有限公司
学习一下显示全部
学习一下收起
互联网服务 · 2012-05-03
浏览983
mcdullermcduller集成工程师郑州正信科技发展有限公司
其实是操作系统的问题,WIN的系统会出现这种问题,因为,在WIN系统中都有有一个主进程服务,WASservice,这种问题,可以再安装目录bin下执行WASservice -remove service_name然后重启服务试试,很多这种情况都能解决...显示全部
其实是操作系统的问题,WIN的系统会出现这种问题,因为,在WIN系统中都有有一个主进程服务,WASservice,这种问题,可以再安装目录bin下执行WASservice -remove service_name然后重启服务试试,很多这种情况都能解决收起
电信设备制造商 · 2012-04-26
浏览966
tonyxu841106tonyxu841106IT顾问Eproe
删除trace log确实好用 ...显示全部
删除trace log确实好用 ...收起
系统集成 · 2012-04-23
浏览957
jevonshujevonshu技术经理九星电子商务有限公司
这个问题我倒是没碰到过,比较诡异。显示全部
这个问题我倒是没碰到过,比较诡异。收起
互联网服务 · 2010-03-30
浏览941
jevonshujevonshu技术经理九星电子商务有限公司
这个问题我倒是没碰到过,比较诡异。显示全部
这个问题我倒是没碰到过,比较诡异。收起
互联网服务 · 2010-03-30
浏览921
xuebinemailxuebinemail项目经理北京某股份有限公司
恩,自己没有遇到过,学习了。显示全部
恩,自己没有遇到过,学习了。收起
系统集成 · 2010-03-29
浏览940
xuebinemailxuebinemail项目经理北京某股份有限公司
恩,自己没有遇到过,学习了。显示全部
恩,自己没有遇到过,学习了。收起
系统集成 · 2010-03-29
浏览920
huangmuhuangmu系统工程师top
这种错误太诡异呀,我就是经常遇见。有时将logs删除(先备份),可以启动了,有时将was进程关掉,可以启动。有没有什么一劳永逸的方法呢?????显示全部
这种错误太诡异呀,我就是经常遇见。有时将logs删除(先备份),可以启动了,有时将was进程关掉,可以启动。有没有什么一劳永逸的方法呢?????收起
IT分销/经销 · 2010-03-29
浏览946
huangmuhuangmu系统工程师top
这种错误太诡异呀,我就是经常遇见。有时将logs删除(先备份),可以启动了,有时将was进程关掉,可以启动。有没有什么一劳永逸的方法呢?????显示全部
这种错误太诡异呀,我就是经常遇见。有时将logs删除(先备份),可以启动了,有时将was进程关掉,可以启动。有没有什么一劳永逸的方法呢?????收起
IT分销/经销 · 2010-03-29
浏览901

提问者

hnyzlboy
项目经理用友软件
擅长领域: 中间件服务器WAS

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